A particle of mass 5 ~m at rest suddenly breaks on its own into three fragments. Two fragments of mass m each move along mutually perpendicular…
NEET UG 2019 — Physics Mechanics
2019mcqmedium
A particle of mass 5m at rest suddenly breaks on its own into three fragments. Two fragments of mass m each move along mutually perpendicular direction with each speed v. The energy released during the process is
Official previous-year question
Held on 30 Apr 2019 · Verified 9 Jul 2026.
Options
A
53mv2
B
35mv2
C
23mv2
D
34mv2
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Solution
The particle of mass 5m breaks in three fragments of mass m,m and 3m respectively. Two fragments of mass meach, move in perpendicular direction with velocity v and the left fragment will move in a direction with velocity v′ such that the total momentum of the system must remain conserved.
By law of conservation of momentum, 5m×0⇒v′∴∣v′∣=mvi^+mvj^+3mv′=−3vi^−3vj^=(−3v)2+(−3v)2=3v2∴ Energy released E=21mv2+21mv2+21×3m(3v2)2=mv2+3mv2=34mv2
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