The Equation of the Trajectory of a Projectile
y=xtan(θ)−2u2cos(θ)gx2
y ,x are Variable and θ is constant
so u2g=constant
52g=32a
a=9.8×259
a=3.5
A projectile is fired from the surface of the earth with a velocity of 5ms−1 and angle θ with the horizontal. Another projectile fired from another planet with a velocity of 3ms−1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is: (given =9.8ms−2)
Held on 30 Apr 2014 · Verified 9 Jul 2026.
3.5
5.9
16.3
110.8
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