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The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2 t^3-6 t^2 The torque on the wheel becomes zero at

NEET UG 2011 — Physics Mechanics

2011mcqhard

The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t3−6t2Q(t)=2 t^3-6 t^2Q(t)=2t3−6t2 The torque on the wheel becomes zero at

Official previous-year question

Held on 30 Apr 2011 · Verified 9 Jul 2026.

Options

  1. A

    t=0.5 st=0.5 \mathrm{~s}t=0.5 s

  2. B

    t=0.25 st=0.25 \mathrm{~s}t=0.25 s

  3. C

    t=2 st=2 \mathrm{~s}t=2 s

  4. D

    t=1 st=1 \mathrm{~s}t=1 s

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