According to question, torque, τ=0 Its means that, α=0 α=dt2d2θ Given So θ(t)=2t3−6t2 dtdθdt2d2θ12t−12t=6t2−12t=12t−12(∵α=dt2d2θ=0)=0=1 s
The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2 t^3-6 t^2 The torque on the wheel becomes zero at
NEET UG 2011 — Physics Mechanics
The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t3−6t2 The torque on the wheel becomes zero at
Held on 30 Apr 2011 · Verified 9 Jul 2026.
Options
- A
t=0.5 s
- B
t=0.25 s
- C
t=2 s
- D
t=1 s
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