The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre I=I1−I2=29MR2−18MR2=1881MR2−MR2=940MR2
NEET UG 2010 — Physics Mechanics
From a circular disc of radius R and mass 9M, a small disc of mass M and radius 3R is removed concentrically. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre is
Held on 30 Apr 2010 · Verified 9 Jul 2026.
940MR2
MR2
4MR2
94MR2
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