If two bodies collide head on with coefficient of restitution e=u1−u2v2−v1 From the law of conservation of linear momentum m1u1+m2u2=m1v1+m2v2⇒v1=[ m1+m2m1−em2]u1+[ m1+m2(1+e)m2]u2 Substituting u1=2 ms−1,u2=0, m1=m and m2=2 m,e=0.5 we get we get ⇒v1=[m+2 mm−m]×2v1=0 Similarly, v2=[ m1+m2(1+e)m1]u1+[ m1+m2m2−em1]u2=[3 m1.5×m]×2=1 ms−1