Finding the angle between the vectors: ∣A×B∣=3(AB)∣A∣∣B∣sin(θ)=3∣ A∣∣B∣cos(θ) Cancelling both sides we get sin(θ)=3cos(θ)cos(θ)sin(θ)=3tan(θ)=3 Hence θ=60∘ Hence the angle between A and B is 60∘
A and B are two vectors and θ is the angle between them, if ∣A×B∣= 3(A⋅B), the value of θ is.
Held on 30 Apr 2007 · Verified 9 Jul 2026.
45∘
30∘
90∘
60∘
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