Applying law of conservation of momentum.
Change in final momentum = initial momentum mvsinθ after collision −(−mvsin θ) before collision f×t= change in momentum =2mvsinθ⇒f=t2mvsinθ Putting the values we get, f=0.252×0.5×12×sin30∘=24 N.
A 0.5 ~kg ball moving with a speed of 12 m / s strikes a hard wall at an angle of 30° with the wall. It is reflected with the same speed at the same…
NEET UG 2006 — Physics Mechanics
A 0.5 kg ball moving with a speed of 12 m/s strikes a hard wall at an angle of 30∘ with the wall. It is reflected with the same speed at the same angle. If the ball is in contact with the wall for 0.25 seconds, the average force acting on the wall is: 
Held on 30 Apr 2006 · Verified 9 Jul 2026.
Options
- A
96 N
- B
48 N
- C
24 N
- D
12 N
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