We know that CM=m1+m2m1x1+m2x2 After changing a position of m1 and to keep the position of C.M. same. C.M. =m1+m2m1(x1d)+m2(x2−d2) 0⇒d2=m1+m2m1d−m2d2=m2m1d
NEET UG 2004 — Physics Mechanics
Consider a system of two particle having masses m1 and m2. If the particle of mas m1 is pushed towards the mass centre of particle through a distance d, by what distance would the particle of mass m2 move so as to keep the mass centre of particles at the original position?
Held on 30 Apr 2004 · Verified 9 Jul 2026.
m1+m2m1d
m2m1d
d
m1m2d
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