Here fmax=μN=μmg =0.5×10×10=50 N ⇒a= mass net force =10100−50=5 m/sec2
NEET UG 2002 — Physics Mechanics
A block of mass 10 kg placed on the rough horizontal surface having coefficient of friction μ=0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be:
Held on 30 Apr 2002 · Verified 9 Jul 2026.
10 ms−1
5 ms−2
15 ms−2
0.5 ms−2
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