L=μ0μr×n×A×N L=μ0μrn×A×lN×l L=μ0μr×n2×A×I⇒L∝n2I ⇒LBLA=nB2nA2×IBIA ⇒LBLA=41×2=21
Let us consider two solenoids A and B, made from same magnetic material of relative permeability μr and equal area of cross-section. Length of A is twice that of B and the number of turns per unit length in A is half that of B. The ratio of self inductances of the two solenoids, LA:LB is
Held on 30 Apr 2024 · Verified 9 Jul 2026.
1:2
2:1
8:1
1:8
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