The potential V at any point, at distance r from centre of dipole =r2KPcosθ At axial point where θ=0∘,V=r2KP=229×109×4×10−6=9×103 V At axial point where θ=180∘,V=r2−KP=−9×103 V
NEET UG 2024 — Physics Electromagnetism
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The potential (V) at any axial point, at 2 m distance (r) from the centre of the dipole of dipole moment vector P of magnitude, 4×10−6Cm, is ±9×103 V. (Take 4πϵ01=9×109 SI units) Reason R : V=±4πϵ0r22P, where r is the distance of any axial point, situated at 2 m from the centre of the dipole. In the light of the above statements, choose the correct answer from the options given below:
Held on 30 Apr 2024 · Verified 9 Jul 2026.
Both A and R are true and R is NOT the correct explanation of A .
A is true but R is false.
A is false but R is true.
Both A and R are true and R is the correct explanation of A.
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