As given in the question,
Ig=0
Potential drop across R will be equal to 2V.
Now, current through the left circuit can be written as,
I=400+R10.
Therefore, potential drop across R will be,
VR=IR⇒2=400+R10R⇒800+2R=10R⇒R=100Ω
NEET UG 2023 — Physics Electromagnetism
2023mcqhard
If the galvanometer G does not show any deflection in the circuit shown, the value of R is given by:
Official previous-year question
Held on 30 Apr 2023 · Verified 9 Jul 2026.
Options
- A
400Ω
- B
200Ω
- C
50Ω
- D
100Ω
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