Given, B=3×10−8cos(1.6×103x +48×1010t) On comparing equations (1) & (2), we get; B0c=3×10−8=kω=1.6×10348×1010=3×108 And also, c= B0E0 Hence, E0=B0×c =3×10−8×3×108=9 So, the required equation is: E=9cos(1.6×103x+48×1010t)
The magnetic field of a plane electromagnetic wave is given by overrightarrow B=3 × 10^-8 cos (1.6 × 10^3 x+ . 48 × 10^10 t) j, then the associated…
NEET UG 2022 — Physics Electromagnetism
2022mcqmedium
The magnetic field of a plane electromagnetic wave is given by B=3×10−8cos(1.6×103x+ 48×1010 t) j^, then the associated electric field will be:
Official previous-year question
Held on 30 Apr 2022 · Verified 9 Jul 2026.
Options
- A
3×10−8cos(1.6×103x+48×1010t)i^/m
- B
3×10−8sin(1.6×103x+48×1010t)i^/m
- C
9sin(1.6×103x−48×1010t)k^ V/m
- D
9cos(1.6×103x+48×1010t)k^ V/m
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