Let net resistance of the given infinite network be ' R ' Now, the circuit can be modified as 
Now, Rnet =R=1+1+R+1R ∴R=2+R+1RR2+R=2R+2+RR2−2R−2=0R=(22±4+8)R=(1+3)Ω
The equivalent resistance of the infinite network given below is: NEET 2022 Physics, Current Electricity — question figure
NEET UG 2022 — Physics Electromagnetism
2022mcqhard
The equivalent resistance of the infinite network given below is: 
Official previous-year question
Held on 30 Apr 2022 · Verified 9 Jul 2026.
Options
- A
2Ω
- B
(1+2)Ω
- C
(1+3)Ω
- D
(1+5)Ω
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