The radius of the bigger drop will be 34πR3=27×34πr3⇒R=3r, the potential of the small drop, V=rKq. The potential of the big drop Q=nq,V′=RKQ⇒V′=RKnqAs we know,V′=n2/3V=(27)2/3×220=1980V
Twenty seven drops of same size are charged at 220V each. They combine to form a bigger drop. Calculate the potential of the bigger drop.
Held on 30 Apr 2021 · Verified 9 Jul 2026.
660V
1320V
1980V
1520V
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