Here, R1=R= ? R2=5Ω,V=10 V and P=30 W Hence PR102R100R=R1V2+R2V2=30−5102=30−20=10Ω
The power dissipated in the circuit shown in the figure is 30 Watt. The value of R is NEET 2012 Physics, Current Electricity — question figure
NEET UG 2012 — Physics Electromagnetism
2012mcqmedium
The power dissipated in the circuit shown in the figure is 30 Watt. The value of R is 
Official previous-year question
Held on 30 Apr 2012 · Verified 9 Jul 2026.
Options
- A
20Ω
- B
15Ω
- C
10Ω
- D
30Ω
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