Induced emf of coil E=−dtdϕt Given, ϕ=50t2+4 and R=400Ω E=−dtdϕt=2=∣100t∣t=2=200 V Current in the coil i=RE=400200=21=0.5 A
NEET UG 2012 — Physics Electromagnetism
A coil of resistance 400Ω is placed in a magnetic field. If the magnetic flux ϕ(Wb) linked with the coil varies with time t (sec) as ϕ=50t2+4 The current in the coil at t=2 s is
Held on 30 Apr 2012 · Verified 9 Jul 2026.
0.5 A
0.1 A
2 A
1 A
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