Given, e=2002sin100t and CErmsXCirmsirms=1μF=200 V=ωC1=1×10−6×1001=104Ω=XCErms=104200=2×10−2 A=20 mA
In an AC circuit an alternating voltage e=200 √2 sin 100 t volt is connected to a capacitor of capacity 1 μ F. The rms value of the current in the…
NEET UG 2011 — Physics Electromagnetism
In an AC circuit an alternating voltage e=2002sin100t volt is connected to a capacitor of capacity 1μF. The rms value of the current in the circuit is
Held on 30 Apr 2011 · Verified 9 Jul 2026.
Options
- A
100 mA
- B
200 mA
- C
20 mA
- D
10 mA
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