R=z+rE 2=2+rE0.5=9+rE From Eqs. (i) and (ii), We have 0.5243rr=2+r9+r=2+r9+r=1=31Ω
NEET UG 2011 — Physics Electromagnetism
A current of 2 A flows through a 2Ω resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9Ω resistor. The internal resistance of the battery is
Held on 30 Apr 2011 · Verified 9 Jul 2026.
1/3Ω
1/4Ω
1Ω
0.5Ω
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