qAqBqCVA VB=4πa2σ,=−4πb2σ,=4πc2σ,c=a+b=4π∈01(aqA+bqB+cqC)=ϵ02σa=4πϵ01(aqA+bqB+cqC) VC=ϵ0σ(ba2−b+c)=ϵ0σ(a+ba2)=4π∈01(aqA+bqB+cqC)=ϵ0σ(ca2−b+c)=ϵ02σa So, VC=VA=VB
NEET UG 2009 — Physics Electromagnetism
Three concentric spherical shells have radii a, b, and c(a<b<c) and have surface charge densities σ,−σ and σ respectively. If VA,VB and VC denote the potentials of the three shells, then, for c=a+b, we have :
Held on 30 Apr 2009 · Verified 9 Jul 2026.
VC=VB=VA
VC=VA=VB
VC=VB=VA
VC=VB=VA
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