Step 1: Total flux through cylinder using Gauss Law By Gauss Law, total flux through the cylinder is given by: ϕtotal =ε0q…(1) Step 2: Flux through plane surface A As surfaces A&C is symmetrical so ϕA=ϕC ϕtotal =ϕA+ϕB+ϕC=εoq[Using Equation (1)] Given Flux through curved surface ϕB=ϕ So, 2ϕA+ϕ=ε0q⇒ϕA=21(ε0q−ϕ)
NEET UG 2007 — Physics Electromagnetism
2007mcqmedium
A hollow cylinder has a charge q coulomb within it. If ϕ is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of voltmeter will be 
Official previous-year question
Held on 30 Apr 2007 · Verified 9 Jul 2026.
Options
- A
2ε0q
- B
3ϕ
- C
ε0q−ϕ
- D
21(ε0q−ϕ)
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