The nuclear reaction is given by:
2X3+Y4→Z10
The total binding energy of the reactants is the sum of the binding energies of the two nuclei of mass number 3 and the nucleus of mass number 4.
Binding energy of reactants =2×(3×5.6)+(4×7.4)
=33.6+29.6=63.2 MeV
The total binding energy of the product nucleus of mass number 10 is:
Binding energy of product =10×6.1=61.0 MeV
The change in mass energy ΔMc2 is equal to the difference in the total binding energies of the reactants and the product.
ΔMc2=∣63.2−61.0∣=2.2 MeV
Answer: 2.2