For hydrogen-like atoms:
V∝nZ and r∝Zn2
Thus r∝Vn
Since the radii are nearly the same:
V1n1=V2n2
n2n1=V2V1=2.5×1053×105=56
Possible order of energy states is 6 and 5.
Two electrons are moving in orbits of two hydrogen like atoms with speeds 3×105 m/s and 2.5×105 m/s respectively. If the radii of these orbits are nearly same then the possible order of energy states are ____ respectively.
Held on 24 Jan 2026 · Verified 6 Jul 2026.
8 and 10
9 and 8
10 and 12
6 and 5
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