The fusion reaction is given by:
212H→24He
Binding energy of one 12H nucleus = 2×1.1=2.2 MeV
Total initial binding energy = 2×2.2=4.4 MeV
Binding energy of 24He nucleus = 4×7.2=28.8 MeV
Energy released ΔE = Final binding energy - Initial binding energy
ΔE=28.8−4.4=24.4 MeV
Answer: 24.4