In Bohr's atom, the energy levels are En=−n2E0 where E0 is the ground state energy.
Given E=−0.04E0, we have −n2E0=−0.04E0, which gives n2=25, so n=5.
The angular momentum in Bohr's model is L=nℏ=n2πh.
Therefore, h2πL=h2π×n2πh=n=5.
The energy of an electron in an orbit of the Bohr's atom is -0.04 E_0 eV where E_0 is the ground state energy. If L is the angular momentum of the…
JEE Main 2026 — Physics Modern Physics
2026mcqmedium
The energy of an electron in an orbit of the Bohr's atom is −0.04E0eV where E0 is the ground state energy. If L is the angular momentum of the electron in this orbit and h is the Planck's constant, then h2πL is ____ :
Official previous-year question
Held on 21 Jan 2026 · Verified 6 Jul 2026.
Options
- A
5
- B
6
- C
2
- D
4
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