For the nucleus 83209Bi, the number of protons is Z=83 and the number of neutrons is N=209−83=126.
Mass of 83 protons =83×1.007825=83.649475u
Mass of 126 neutrons =126×1.008665=127.091790u
Total mass of the nucleons =83.649475+127.091790=210.741265u
The mass defect Δm is given by:
Δm=Total mass of nucleons−Mass of nucleus
Δm=210.741265−208.980388=1.760877u
The total binding energy (BE) is:
BE=Δm×931MeV
BE=1.760877×931=1639.376MeV
The binding energy per nucleon is:
ABE=2091639.376≈7.84MeV
Answer: 7.84