Using Einstein's photoelectric equation:
K1=λ1hc−ϕ
K2=λ2hc−ϕ
Given λ1=2λ2, the first equation becomes:
K1=2λ2hc−ϕ
Multiplying by 2:
2K1=λ2hc−2ϕ
Substituting λ2hc=K2+ϕ from the second equation:
2K1=(K2+ϕ)−2ϕ
2K1=K2−ϕ
ϕ=K2−2K1
Answer: K2−2K1