Energy of photon =E=λhc ⇒ Wavelength of photon =λ=Ehc Energy of proton =E=21mpv2=2mpP2 ⇒ Linear momentum of proton =P=2mpE Or de-Broglie wavelength of proton $\begin{aligned}
=\lambda_p= & \frac{h}{P}=\frac{h}{\sqrt{2 m_p E}} \
\text { Ratio } \frac{\lambda_p}{\lambda} & =\frac{h}{\sqrt{2 m_p E}} \times \frac{E}{h c} \
& =\frac{1}{c} \sqrt{\frac{E}{2 m_p}}
\end{aligned}$