Given lights are of same wavelength. Hence stopping potential will remain same. Since I2>I1, hence saturation current corresponding to I2 will be greater than that corresponding to I1.
Which figure shows the correct variation of applied potential difference (V) with photoelectric current (I) at two different intensities of light (I1<I2) of same wavelengths :
Held on 4 Apr 2024 · Verified 6 Jul 2026.




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