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The disintegration energy Q for the nuclear fission of ^235 U → ^140 Ce+ ^94 Zr+n is MeV. Given atomic masses of ^235 U: 235.0439 u ; ^140 Ce:…

JEE Main 2024 — Physics Modern Physics

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The disintegration energy QQQ for the nuclear fission of 235U→140Ce+94Zr+n{ }^{235} \mathrm{U} \rightarrow{ }^{140} \mathrm{Ce}+{ }^{94} \mathrm{Zr}+n235U→140Ce+94Zr+n is ______ MeV\mathrm{MeV}MeV. Given atomic masses of 235U:235.0439u;140Ce:139.9054u{ }^{235} \mathrm{U}: 235.0439 u ;{ }^{140} \mathrm{Ce}: 139.9054 u235U:235.0439u;140Ce:139.9054u, 94Zr:93.9063u;n:1.0086u, { }^{94} \mathrm{Zr}: 93.9063 u ; n: 1.0086 u \text {, }94Zr:93.9063u;n:1.0086u,  Value of c2=931MeV/uc^2=931 \mathrm{MeV} / \mathrm{u}c2=931MeV/u

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