235U→140Ce+94Zr+n
Disintegration energy $\begin{aligned}
\mathrm{Q} & =\left(\mathrm{m}{\mathrm{R}}-\mathrm{m}{\mathrm{p}}\right) \mathrm{c}^2 \
\mathrm{~m}{\mathrm{R}} & =235.0439 \mathrm{u} \
\mathrm{m}{\mathrm{p}} & =139.9054 \mathrm{u}+93.9063 \mathrm{u}+1.0086 \mathrm{u} \
& =234.8203 \mathrm{u} \
\mathrm{Q} & =(235.0439 \mathrm{u}-234.8203 \mathrm{u}) \mathrm{c}^2 \
& =0.2236 \mathrm{c}^2 \
& =0.2236 \times 931 \
\mathrm{Q} & =208.1716
\end{aligned}$