For photon,
EP=λphc⇒λp=EPhc
For electron
λe==meveh2Kehve
Given ve=0.25c. So,
λe==2Keh×0.25c8Kehc
Also λp=λe. Thus,
Ephc=8Kehc⇒EpKe=81
The de-Broglie wavelength of an electron is the same as that of a photon. If velocity of electron is 25 of the velocity of light, then the ratio of K.E. of electron and K.E. of photon will be:
Held on 29 Jan 2024 · Verified 6 Jul 2026.
11
81
18
41
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