Given the nuclear reaction is
C136+Energy→C126+n10
The mass defect for the above reaction can be calculated as follows:
Δm==[(12.000000+1.008665)−13.003354]u−0.00531u
Hence, the energy required is given by
E==0.00531×931.5MeV4.95MeV
The atomic mass of C126 is 12.000000u and that of C136 is 13.003354u. The required energy to remove a neutron from C136, if mass of neutron is 1.008665u, will be:
Held on 27 Jan 2024 · Verified 6 Jul 2026.
62.5MeV
6.25MeV
4.95MeV
49.5MeV
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