In the Paschen radiation series, the longest wavelength corresponds to the transition between n=3 and n=4.
The formula for the wavelength in the given transition can be written as,
λ1=RZ2(n121−n221)...(1)
From equation (1), it follows that
λ1=RZ2(321−421)=RZ2(91−161)=9×167RZ2⇒λ=7R144
Hence, α=144.