$\begin{aligned}
& \mathrm{eV}_0=\mathrm{hv}-\phi \
& \mathrm{V}_0=\frac{\mathrm{h}}{\mathrm{e}} \mathrm{v}-\frac{\phi}{\mathrm{e}}
\end{aligned}\mathrm{M}_2$ material has higher work function, so statement-(II) is incorrect.
JEE Main 2024 — Physics Modern Physics
2024mcqeasy
Given below are two statements : 
Statement I : Figure shows the variation of stopping potential with frequency (v) for the two photosensitive materials M1 and M2. The slope gives value of eh, where h is Planck's constant, e is the charge of electron. Statement II : M2 will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency. In the light of the above statements, choose the most appropriate answer from the options given below.
Official previous-year question
Held on 5 Apr 2024 · Verified 6 Jul 2026.
Options
- A
Both Statement I and Statement II are correct
- B
Statement I is incorrect but Statement II is correct
- C
Both Statement I and Statement II are incorrect
- D
Statement I is correct and Statement II is incorrect
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