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As Zener is in breakdown region, therefore potential drop across it would be 10V. Now,
I3=50010=501A and
I1=20010=201A
Also, I2=I1−I3
⇒I2=(201−501)=(1003)A=30mA
A Zener diode of breakdown voltage 10V is used as a voltage regulator as shown in the figure. The current through the Zener diode is
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Held on 30 Jan 2024 · Verified 6 Jul 2026.
50mA
0
30mA
20mA
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