The de-Broglie wavelength in the first case is
λ=2mEh
In the second case the kinetic energy is K=4E.
Let the de-Broglie wavelength be λ′.
The value of wavelength is
λ′=2m4Eh=2mE2h=2λ
JEE Main 2023 — Physics Modern Physics
The de Broglie wavelength of an electron having kinetic energy E is λ. If the kinetic energy of electron becomes 4E, then its de-Broglie wavelength will be:
Held on 15 Apr 2023 · Verified 6 Jul 2026.
2λ
2λ
2λ
2λ
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