Given:
Binding energy, EH=E0=13.6eV.
Now for hydrogen like atom, we can write
ELi2+=E0n2Z2=13.6×99=13.6eV
=136×10−1eV
Therefore, x=136.
JEE Main 2023 — Physics Modern Physics
If the binding energy of ground state electron in a hydrogen atom is 13.6eV, then, the energy required to remove the electron from the second excited state of Li2+ will be: x×10−1eV. The value of x is _____.
Held on 31 Jan 2023 · Verified 6 Jul 2026.
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