The energy of a photon is given by E=λhc.
It is given that λ1=500nm, λ2=600nm.
The net energy absorbed is
ΔE=λ1hc−λ2hc=10−9hc(5001−6001)
=500×600×10−96.6×10−34×3×108×100
=306.6×3×10−19J
1eV=1.6×10−19J
=30×1.66.6×3eV
=4125×10−4eV
An atom absorbs a photon of wavelength 500nm and emits another photon of wavelength 600nm. The net energy absorbed by the atom in this process is n×10−4eV. The value ofnis [Assume the atom to be stationary during the absorption and emission process] (Take h=6.6×10−34Js and c=3\times 108 m s-1 ).
Held on 13 Apr 2023 · Verified 6 Jul 2026.
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