Using the relation between energy of photon and wavelength for the transition in the hydrogen atom, we get
λhc=13.6[n121−n221]
⇒λ4×10−15×3×108=13.6[1−161]⇒λ=13.6×1512×10−7×16=94.1×10−9=94.1nm
JEE Main 2023 — Physics Modern Physics
A photon is emitted in transition from n=4ton=1 level in hydrogen atom. The corresponding wavelength for this transition is (given, h=4×10−15eVs)
Held on 24 Jan 2023 · Verified 6 Jul 2026.
941nm
974nm
99.3nm
94.1nm
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