Let the electron jumped to nth excited state.
In the ground state, energy E=−13.6eV
So, using relation 12.75=13.6[121−n21]
⇒0.9375=[1−n21]⇒n2=16
⇒n=16=4
Now, angular momentum, L=2πnh=2π4h=π2h
=π2×4.14×10−15
=π828×10−17eVs
Hence, the value of x=828.