De-Broglie wavelength for electron is given by, λe=2mkh
For photon k=λphc⇒λp=khc. Therefore,
λe=2mhchλp
λp∝λe2
The de Broglie wavelengths for an electron and a photon are λe and λp respectively. For the same kinetic energy of electron and photon, which of the following presents the correct relation between the de Broglie wavelengths of two?
Held on 28 Jun 2022 · Verified 6 Jul 2026.
λp∝λe2
λp∝λe
λp∝λe
λp∝λe1
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