We have, λp=pph and λe=peh
Given here, λe=λp, then pp=pe
Ratio of their energy is EphEe=hc\lambda Ppe22m=2mcpe=2mcmv=2cv
JEE Main 2022 — Physics Modern Physics
An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are Ee and Pe and that of photon are Eph and Pph respectively. Which of the following is correct?
Held on 26 Jun 2022 · Verified 6 Jul 2026.
EphEe=v2c
EphEe=2cv
pphpe=v2c
pphpe=2cv
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