Let I1 be the current through Zener diode and I2 through load resistor.
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As maximum current flows through Zener diode, hence I2=0.
∴Maximum current, I=I1+I2=25mA+0=25mA
Here, Vo is voltage drop across Zener =8V.
Since I is maximum, hence minimum value of R
R=VoVi−=25×10−320−8=480Ω