Energy absorbed is given by,
ΔE=13.6×(n121−n221)
10.2=13.6×(n121−n221)
Therefore, we get, {n}_{1}=1&{n}_{2}=2
The change in angular momentum
ΔL=2πn2h−2πn1h=2πh
=1.05×10−34Js
A hydrogen atom in its ground state absorbs 10.2eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of (Given, Planck's constant =6.6×10−34Js).
Held on 27 Jun 2022 · Verified 6 Jul 2026.
2.10×10−34Js
1.05×10−34Js
3.15×10−34Js
4.2×10−34Js
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