KEmax=hν−ϕ
21mv2=hν−ϕ
v=m2(hν−ϕ)
Given hν1=2ϕ
hν2=10ϕ
∴v2v1=hν2−ϕhν1−ϕ
v2v1=10ϕ−ϕ2ϕ−ϕ=31
JEE Main 2021 — Physics Modern Physics
Two stream of photons, possessing energies equal to twice and ten times the work function of metal are incident on the metal surface successively. The value of ratio of maximum velocities of the photoelectrons emitted in the two respective cases is x:3 The value of x is
Held on 26 Feb 2021 · Verified 6 Jul 2026.
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