Time taken to revolve in circular orbit is T=ω2π=v2πr=2.2×1062×722×5×10−11=710×10−16s
Now, current associated with the electron is I=Te=710×10−161.6×10−19=1.12×10−3A
⇒I=1.12mA
Hence, the current is 112×102mA.
In Bohr's atomic model, the electron is assumed to revolve in a circular orbit of radius 0.5A∘. If the speed of electron is 2.2×106ms−1. Then the current associated with the electron will be__________ ×10−2mA. [Take π as 722]
Held on 27 Jul 2021 · Verified 6 Jul 2026.
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