λdeb=ph=2mKEh
If λ is same the P will be same
KE∝1/m
mp>me⇒Kp<Ke
A moving proton and electron have the same de-Broglie wavelength. If K and P denote the K.E. and momentum respectively. Then choose the correct option :
Held on 31 Aug 2021 · Verified 6 Jul 2026.
Kp>Ke and Pp=Pe
Kp<Ke and Pp=Pe
Kp<Keand Pp<Pe
Kp=Ke and Pp=Pe
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