
v1=(2m+3m)2(m/3)0+(2m+3m)(2m−3m)v=5v
For particle A,
Initial de-Broglie wavelength
λ0=2mvh=mv2h
Final de-Broglie wavelength after collision.
λ1=2m5vh=mv10h=5λ0
Change in De-Broglie wavelength Δλ=λi−λ0=4λ0
JEE Main 2020 — Physics Modern Physics
Particle A of mass mA=2m moving along the x -axis with velocity v0 collides elastically with another particle B at rest having mass mB=3m. If both the particles move along the x -axis after the collision, the change Δλ in the wavelength of the particle A, in terms of its de-Broglie wavelength (λ0) before the collision is:
Held on 4 Sept 2020 · Verified 6 Jul 2026.
Δλ=23λ0
Δλ=25λ0
Δλ=2λ0
Δλ=4λ0
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