For n+p→d+γ,
The mass defect, Δm=mp+mn−md
⇒Δm=1.0072+1.0087−2.0141
⇒Δm=0.0018
⇒Δm>0
∴onlyn+p→d+γispossible
JEE Main 2020 — Physics Modern Physics
Given the masses of various atomic particles mP=1,0072u, mn=1,0087u, me=0.000548u, mvˉ=0, md=2.0141u, where p=proton, n≡neutron, e≡electron, vˉ≡antineutrino and dˉ≡deuteron. Which of the following process is allowed by momentum and energy conservation :
Held on 6 Sept 2020 · Verified 6 Jul 2026.
n+n→ deuterium atom (electron bound to the nucleus)
p→n+e++vˉ
n+p→d+γ
e++e−→γ
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