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Find the Binding energy per nucleon for Sn50120. Mass of proton m_ =1.00783U, mass of neutron m_n=1.00867U and mass of tin nucleus m_ sn=119.902199U.…

JEE Main 2020 — Physics Modern Physics

2020mcqmedium

Find the Binding energy per nucleon for Sn50120\mathrm{Sn}50120Sn50120. Mass of proton mp=1.00783U{m}_{p}=1.00783Ump​=1.00783U, mass of neutron mn=1.00867U{m}_{n}=1.00867Umn​=1.00867U and mass of tin nucleus msn=119.902199U{m}_{\mathrm{sn}}=119.902199Umsn​=119.902199U. (take 1U=931MeV1U=931MeV1U=931MeV)

Official previous-year question

Held on 4 Sept 2020 · Verified 6 Jul 2026.

Options

  1. A

    7.5MeV7.5MeV7.5MeV

  2. B

    9.0MeV9.0MeV9.0MeV

  3. C

    8.0MeV8.0MeV8.0MeV

  4. D

    8.5MeV8.5MeV8.5MeV

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